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Temple City Institute of Technology and Engineering (TITE), Khorda Admission 2023: M.Sc. Admission, Application process
TITE is a private engineering institute located at Khorda, Odisha. This institute was established in 2007 and is a part of Techno India group. TITE Khorda offers B.Tech. course with seven specializations and M. Tech. course with one specialization in Computer Science. The course and syllabus of these programs will be as per Biju Patnaik University of Technology (BPUT), Orissa.
- For B.Tech., any candidate who has passed class 12th with PCM subjects will be eligible to apply.
- The selection will be done on the basis Orissa JEE or AIEEE entrance test.
- For M.Tech., passing of B.Tech. is mandatory for applying to this course.
- The selection will be OJEE score based.
Read More: TITE Khorda Fee Structure
Temple City Institute of Technology and Engineering (TITE), Khorda B.Tech. Admission 2023
TITE offers B.Tech. and B.Tech. course with seven specializations of 4 years each.
| Course Name | Specialization | Eligibility Criteria | Selection Criteria | Duration |
|---|---|---|---|---|
| B.Tech. | Electronics and Communication Engineering | Must have passed +2 with PCM subjects from CHSE Orissa or equivalent | Orissa JEE or AIEEE entrance examination | 4 years |
| Electrical and Electronics Engineering | ||||
| Computer Science and Engineering | ||||
| Information and Technology Engineering | ||||
| Mechanical Engineering | ||||
| Electrical Engineering | ||||
| Civil Engineering | ||||
| B.Tech. (Lateral Entry) | Electronics and Communication Engineering | Must have passed Diploma or have done B.Sc. with Mathematics as a compulsory subject in the related discipline | OJEE entrance test | 3 years |
| Electrical and Electronics Engineering | ||||
| Computer Science and Engineering | ||||
| Information and Technology Engineering | ||||
| Mechanical Engineering | ||||
| Electrical Engineering | ||||
| Civil Engineering |
Temple City Institute of Technology and Engineering (TITE), Khorda M.Sc. Admission 2023
TITE offers one course under its post graduation wing which is M.Sc. in Computer Science and Engineering. The eligibility for applying to this course is a pass in B.Tech. in the same field. The selection will be done on the basis of the score obtained by the candidate in the GATE entrance exam.
| Course Name | Specialization | Eligibility Criteria | Selection Criteria | Duration |
|---|---|---|---|---|
| M.Sc. | Computer Science and Engineering | Must have passed B.Tech. in the field of CS | GATE Score | 2 years |
Temple City Institute of Technology and Engineering (TITE), Khorda Application Process 2023
A candidate wanting to apply to any of the courses offered by the university can do it by following the below given steps.
- Visit the official website.
- Click on Admissions followed by Apply Now.
- Click on the Register.
- Fill all the required details.
- Make the registration payment
Do you think the Admission details are wrong ? Report Here
TITE Upcoming Application Dates 2025
Important Events
| Events | Dates |
|---|---|
| JEE Main 2025 Exam Date | Jan 25, 2025 - Jan 31, 2025 |
Expired Events
| Events | Dates |
|---|---|
| Admission Timeline (BE/B.Tech) [OJEE] | Jul 06, 2024 - Aug 19, 2024 |
Important Events
| Events | Dates |
|---|---|
| JEE Main 2025 Exam Date | Jan 25, 2025 - Jan 31, 2025 |
Expired Events
| Events | Dates |
|---|---|
| Admission Timeline (BE/B.Tech) [OJEE] | Jul 06, 2024 - Aug 19, 2024 |
Do you think the Dates are wrong ? Report Here
TITE Cutoff 2025
Exams
TITE, OJEE Cutoff 2023
TITE, OJEE Cutoff 2023 for General Category is listed below. The overall cutoff rank for OJEE is 1104961
| Courses | Round 1 |
|---|---|
| 1104961 |
TITE, JEE Main Cutoff 2022
TITE, JEE Main Cutoff 2022 for General Category is listed below. The overall cutoff rank for JEE Main is 1503066 - 1507134
| Courses | Round 1 |
|---|---|
| 1503066 | |
| 1504471 | |
| 1506589 |
Do you think the Cutoff is wrong ? Report Here
| COURSE | ADMISSION LINK |
|---|---|
| BE/B.Tech, | Admission Link |
Do you think the data is wrong ? Report Here
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