Which is better, applied math at IIT Roorkee or CSE at any of the newer IITs like IIT Bhubaneswar or Jodhpur?

CSE is a branch with unlimited opportunities and wide scope to explore. Opting for a CSE branch at a new IIT will surely let you explore many opportunities and will provide a good package as well. Looking at the placement statistics, IIT Jodhpur offers 16.73 LPA of average package whereas IIT Bhubaneshwar offers an average package of 11.44 LPA for CSE students. Both the IITs have placed 100% of their students, as per record of 2019. If you are interested to pursue CSE as your domain in graduation then preferring CSE at new IITs would be better.

Whereas, if you have an interest in research and pure Mathematics then you should opt for ‘Applied Mathematics’ at IIT Roorkee. IIT Roorkee offers two courses in Applied Mathematics viz. ‘Integrated M.Sc. (Applied Mathematics)’ of 5 years and ‘Two years M.Sc. (Mathematics)’ of 2 years. There are 30 seats in total for this course and the average package offered during placement is around 14.73 LPA. Companies like Adobe recruits 2 students each year offering the package of 38 LPA. Other companies that come for placement are Accenture, Goldman Sach Services, American Express, De Shaw. Moreover, top core IITs provide many opportunities in curricular activities too.