KCET 2004 Biology Question Paper with Answer Key pdf is available for download. The exam was conducted by Karnataka Examination Authority (KEA) on May 18, 2004 in the Morning Session 10:30 AM to 11:50 AM. The question paper comprised a total of 60 questions.
KCET 2004 Biology Question Paper with Answer Key PDF
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KCET Questions
1. A vessel at 1000 K contains $CO_2$ with a pressure of 0.5 atm. Some of the $CO_2$ is converted into CO on the addition of graphite. It the total pressure at equilibrium is 0.8 atm, the value of K is
A vessel at 1000 K contains $CO_2$ with a pressure of 0.5 atm. Some of the $CO_2$ is converted into CO on the addition of graphite. It the total pressure at equilibrium is 0.8 atm, the value of K is
- 3 atm
- 0.3 atm
- 0.18 atm
- 1.8 atm
2. Alary muscle is associated with
Alary muscle is associated with
- heart & circulation
- malpighian tubules & excretion
- trachea & respiration
- none of the above
3. A vessel of one litre capacity containing $1$ mole of $SO_3$ is heated till a state of equilibrium is attained.
$ {2SO3_{(g)} <=> 2SO2_{(g)} + O2_{(g)}}$
At equilibrium, $0.6 \,moles$ of $SO_2$ had formed. The value of equilibrium constant is
A vessel of one litre capacity containing $1$ mole of $SO_3$ is heated till a state of equilibrium is attained.
$ {2SO3_{(g)} <=> 2SO2_{(g)} + O2_{(g)}}$
At equilibrium, $0.6 \,moles$ of $SO_2$ had formed. The value of equilibrium constant is
- 0.18
- 0.36
- 0.45
- 0.68
5. On the basis of standard electrode potential of redox couples given below, find out which of the following is the strongest oxidising agent.
(E$^{\circ}$ values : $Fe^{3+}\left| Fe^{2+}=+ 0.77 V ;
I_{2\left(s\right)}\right|I^{- } =$ $+ 0.54 V; Cu^{2+}\left|Cu= + .34 V ; Ag^{+}\right| Ag = + 0.80 V$)
On the basis of standard electrode potential of redox couples given below, find out which of the following is the strongest oxidising agent.
(E$^{\circ}$ values : $Fe^{3+}\left| Fe^{2+}=+ 0.77 V ;
I_{2\left(s\right)}\right|I^{- } =$ $+ 0.54 V; Cu^{2+}\left|Cu= + .34 V ; Ag^{+}\right| Ag = + 0.80 V$)
- $Fe^{3+}$
- $I_{2(s)}$
- $Cu^{2+}$
- $Ag^{+}$
6. After absorbring a slowly moving neutron of Mass mN (momentum $\approx$ 0) a nucleus of mass M breaks into two nuclei of masses $m_1$ and $5m_1$ ($6\, m_1 = M + mN$ ) respectively. If the de Broglic wavelength of the nucleus with mass $m_1$ is $\lambda$, the de Broglie wevelength of the nucleus will be:
After absorbring a slowly moving neutron of Mass mN (momentum $\approx$ 0) a nucleus of mass M breaks into two nuclei of masses $m_1$ and $5m_1$ ($6\, m_1 = M + mN$ ) respectively. If the de Broglic wavelength of the nucleus with mass $m_1$ is $\lambda$, the de Broglie wevelength of the nucleus will be:
- $5\,\lambda$
- $\lambda $\5
- $\lambda$
- $25\,\lambda$
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